2(x^2-x)=-5x^2-3

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Solution for 2(x^2-x)=-5x^2-3 equation: 



2(x^2-x)=-5x^2-3

We move all terms to the left:

2(x^2-x)-(-5x^2-3)=0

We multiply parentheses

-(-5x^2-3)+2x^2-2x=0

We get rid of parentheses

5x^2+2x^2-2x+3=0

We add all the numbers together, and all the variables

7x^2-2x+3=0

a = 7; b = -2; c = +3;
Δ = b2-4ac
Δ = -22-4·7·3
Δ = -80
Delta is less than zero, so there is no solution for the equation

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